3.8.32 \(\int \frac {1}{x \sqrt {a+b x} \sqrt {a c-b c x}} \, dx\)

Optimal. Leaf size=42 \[ -\frac {\tanh ^{-1}\left (\frac {\sqrt {a+b x} \sqrt {a c-b c x}}{a \sqrt {c}}\right )}{a \sqrt {c}} \]

________________________________________________________________________________________

Rubi [A]  time = 0.02, antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {92, 208} \begin {gather*} -\frac {\tanh ^{-1}\left (\frac {\sqrt {a+b x} \sqrt {a c-b c x}}{a \sqrt {c}}\right )}{a \sqrt {c}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x*Sqrt[a + b*x]*Sqrt[a*c - b*c*x]),x]

[Out]

-(ArcTanh[(Sqrt[a + b*x]*Sqrt[a*c - b*c*x])/(a*Sqrt[c])]/(a*Sqrt[c]))

Rule 92

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]*((e_.) + (f_.)*(x_))), x_Symbol] :> Dist[b*f, Subst[I
nt[1/(d*(b*e - a*f)^2 + b*f^2*x^2), x], x, Sqrt[a + b*x]*Sqrt[c + d*x]], x] /; FreeQ[{a, b, c, d, e, f}, x] &&
EqQ[2*b*d*e - f*(b*c + a*d), 0]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin {align*} \int \frac {1}{x \sqrt {a+b x} \sqrt {a c-b c x}} \, dx &=b \operatorname {Subst}\left (\int \frac {1}{-a^2 b c+b x^2} \, dx,x,\sqrt {a+b x} \sqrt {a c-b c x}\right )\\ &=-\frac {\tanh ^{-1}\left (\frac {\sqrt {a+b x} \sqrt {a c-b c x}}{a \sqrt {c}}\right )}{a \sqrt {c}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.03, size = 63, normalized size = 1.50 \begin {gather*} -\frac {\sqrt {a^2-b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {a^2-b^2 x^2}}{a}\right )}{a \sqrt {a+b x} \sqrt {c (a-b x)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x*Sqrt[a + b*x]*Sqrt[a*c - b*c*x]),x]

[Out]

-((Sqrt[a^2 - b^2*x^2]*ArcTanh[Sqrt[a^2 - b^2*x^2]/a])/(a*Sqrt[c*(a - b*x)]*Sqrt[a + b*x]))

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.09, size = 39, normalized size = 0.93 \begin {gather*} -\frac {2 \tanh ^{-1}\left (\frac {\sqrt {a c-b c x}}{\sqrt {c} \sqrt {a+b x}}\right )}{a \sqrt {c}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/(x*Sqrt[a + b*x]*Sqrt[a*c - b*c*x]),x]

[Out]

(-2*ArcTanh[Sqrt[a*c - b*c*x]/(Sqrt[c]*Sqrt[a + b*x])])/(a*Sqrt[c])

________________________________________________________________________________________

fricas [A]  time = 1.38, size = 110, normalized size = 2.62 \begin {gather*} \left [\frac {\log \left (-\frac {b^{2} c x^{2} - 2 \, a^{2} c + 2 \, \sqrt {-b c x + a c} \sqrt {b x + a} a \sqrt {c}}{x^{2}}\right )}{2 \, a \sqrt {c}}, -\frac {\sqrt {-c} \arctan \left (\frac {\sqrt {-b c x + a c} \sqrt {b x + a} a \sqrt {-c}}{b^{2} c x^{2} - a^{2} c}\right )}{a c}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x+a)^(1/2)/(-b*c*x+a*c)^(1/2),x, algorithm="fricas")

[Out]

[1/2*log(-(b^2*c*x^2 - 2*a^2*c + 2*sqrt(-b*c*x + a*c)*sqrt(b*x + a)*a*sqrt(c))/x^2)/(a*sqrt(c)), -sqrt(-c)*arc
tan(sqrt(-b*c*x + a*c)*sqrt(b*x + a)*a*sqrt(-c)/(b^2*c*x^2 - a^2*c))/(a*c)]

________________________________________________________________________________________

giac [A]  time = 1.26, size = 65, normalized size = 1.55 \begin {gather*} -\frac {2 \, \sqrt {-c} \arctan \left (\frac {{\left (\sqrt {-b c x + a c} \sqrt {-c} - \sqrt {2 \, a c^{2} + {\left (b c x - a c\right )} c}\right )}^{2}}{2 \, a c^{2}}\right )}{a {\left | c \right |}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x+a)^(1/2)/(-b*c*x+a*c)^(1/2),x, algorithm="giac")

[Out]

-2*sqrt(-c)*arctan(1/2*(sqrt(-b*c*x + a*c)*sqrt(-c) - sqrt(2*a*c^2 + (b*c*x - a*c)*c))^2/(a*c^2))/(a*abs(c))

________________________________________________________________________________________

maple [B]  time = 0.04, size = 85, normalized size = 2.02 \begin {gather*} -\frac {\sqrt {b x +a}\, \sqrt {-\left (b x -a \right ) c}\, \ln \left (\frac {2 a^{2} c +2 \sqrt {a^{2} c}\, \sqrt {-\left (b^{2} x^{2}-a^{2}\right ) c}}{x}\right )}{\sqrt {-\left (b^{2} x^{2}-a^{2}\right ) c}\, \sqrt {a^{2} c}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/(b*x+a)^(1/2)/(-b*c*x+a*c)^(1/2),x)

[Out]

-(b*x+a)^(1/2)*(-c*(b*x-a))^(1/2)*ln(2*(a^2*c+(a^2*c)^(1/2)*(-c*(b^2*x^2-a^2))^(1/2))/x)/(-c*(b^2*x^2-a^2))^(1
/2)/(a^2*c)^(1/2)

________________________________________________________________________________________

maxima [A]  time = 0.89, size = 47, normalized size = 1.12 \begin {gather*} -\frac {\log \left (\frac {2 \, a^{2} c}{{\left | x \right |}} + \frac {2 \, \sqrt {-b^{2} c x^{2} + a^{2} c} a \sqrt {c}}{{\left | x \right |}}\right )}{a \sqrt {c}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x+a)^(1/2)/(-b*c*x+a*c)^(1/2),x, algorithm="maxima")

[Out]

-log(2*a^2*c/abs(x) + 2*sqrt(-b^2*c*x^2 + a^2*c)*a*sqrt(c)/abs(x))/(a*sqrt(c))

________________________________________________________________________________________

mupad [B]  time = 2.22, size = 92, normalized size = 2.19 \begin {gather*} -\frac {\left (\ln \left (\frac {\sqrt {c\,\left (a-b\,x\right )}-\sqrt {a\,c}}{\sqrt {a+b\,x}-\sqrt {a}}\right )-\ln \left (\frac {{\left (\sqrt {c\,\left (a-b\,x\right )}-\sqrt {a\,c}\right )}^2}{{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^2}-c\right )\right )\,\sqrt {a\,c}}{a^{3/2}\,c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*(a*c - b*c*x)^(1/2)*(a + b*x)^(1/2)),x)

[Out]

-((log(((c*(a - b*x))^(1/2) - (a*c)^(1/2))/((a + b*x)^(1/2) - a^(1/2))) - log(((c*(a - b*x))^(1/2) - (a*c)^(1/
2))^2/((a + b*x)^(1/2) - a^(1/2))^2 - c))*(a*c)^(1/2))/(a^(3/2)*c)

________________________________________________________________________________________

sympy [C]  time = 5.07, size = 83, normalized size = 1.98 \begin {gather*} \frac {i {G_{6, 6}^{5, 3}\left (\begin {matrix} \frac {3}{4}, \frac {5}{4}, 1 & 1, 1, \frac {3}{2} \\\frac {1}{2}, \frac {3}{4}, 1, \frac {5}{4}, \frac {3}{2} & 0 \end {matrix} \middle | {\frac {a^{2}}{b^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}} a \sqrt {c}} - \frac {{G_{6, 6}^{2, 6}\left (\begin {matrix} 0, \frac {1}{4}, \frac {1}{2}, \frac {3}{4}, 1, 1 & \\\frac {1}{4}, \frac {3}{4} & 0, \frac {1}{2}, \frac {1}{2}, 0 \end {matrix} \middle | {\frac {a^{2} e^{- 2 i \pi }}{b^{2} x^{2}}} \right )}}{4 \pi ^{\frac {3}{2}} a \sqrt {c}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x+a)**(1/2)/(-b*c*x+a*c)**(1/2),x)

[Out]

I*meijerg(((3/4, 5/4, 1), (1, 1, 3/2)), ((1/2, 3/4, 1, 5/4, 3/2), (0,)), a**2/(b**2*x**2))/(4*pi**(3/2)*a*sqrt
(c)) - meijerg(((0, 1/4, 1/2, 3/4, 1, 1), ()), ((1/4, 3/4), (0, 1/2, 1/2, 0)), a**2*exp_polar(-2*I*pi)/(b**2*x
**2))/(4*pi**(3/2)*a*sqrt(c))

________________________________________________________________________________________